26 4
x 6 = 24 (area of yellow)
x 34 4 x
20 = 80 (area of green)
30 x 6 = 180 (area of blue)
30 x 20 = 600 (area of red)
24
80
180
+600
884
Relationship between a
visual model
and the standard division
algorithm.
584 ÷ 23
If
584 square units are to be arranged in a rectangle with edge 23, one way to
begin is to first determine how many ‘bands’ or lengths of 10 can be
incorporated into the rectangle. Each ‘band’ or length 10 will contain 230
units (23 x 10), two ‘bands’ can be used. These 2 ‘bands’ total 460 units
leaving 124 units to be distributed in bands of width 1. Each band of width 1
contains 23 units. So, 5 of these bands can be added, which incorporates an
additional 115 units into the rectangle. This leaves 9 units and this is not
sufficient for another column. Therefore, the quotient is 25 with a remainder
of 9.
![]()
a
![]()
d
2 5
23
![]()
5 8 4
4
6 0 b
1
2 4 c
1
1 5 e
9
f
a)
record the maximum number of bands of width 10 (2),
b)
record the number of units in the bands of width 10 (460),
c)
determine the number of units left to be distributed (124),
d)
record the maximum number of bands of width 1 (5),
e)
record the number of units in the bands of width 1 (115),
f)
determine the remainder (9).